Post on the topic of trigonometry for the telegram channel of the mathematics training center


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https:discord.comchannels@me11825129364015063651182860384391135262 将此图融入到天空中

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A highly detailed airbrush painting, using a parametric equation to create captivating art, x(t) = A * cos(a * t) * cos(t) + A * sin(b * t) * cos(t) and y(t) = A * cos(a * t) * sin(t) + A * sin(b * t) * sin(t), where 'A', 'a', and 'b' are constants, and 't' ranges from 0 to 2π. By experimenting with different values for 'A', 'a', and 'b', you can generate a variety of intriguing and visually appealing designs, combine this with other artistic elements and styles to create a captivating abstract design --ar 3:2

A highly detailed airbrush painting, using a parametric equation to create captivating art, x(t) = A * cos(a * t) * cos(t) + A * sin(b * t) * cos(t) and y(t) = A * cos(a * t) * sin(t) + A * sin(b * t) * sin(t), where 'A', 'a', and 'b' are constants, and 't' ranges from 0 to 2π. By experimenting with different values for 'A', 'a', and 'b', you can generate a variety of intriguing and visually appealing designs, combine this with other artistic elements and styles to create a captivating abstract design --ar 3:2

A highly detailed airbrush painting, using a parametric equation to create captivating art, x(t) = A * cos(a * t) * cos(t) + A * sin(b * t) * cos(t) and y(t) = A * cos(a * t) * sin(t) + A * sin(b * t) * sin(t), where 'A', 'a', and 'b' are constants, and 't' ranges from 0 to 2π. By experimenting with different values for 'A', 'a', and 'b', you can generate a variety of intriguing and visually appealing designs, combine this with other artistic elements and styles to create a captivating abstract design --ar 3:2

A highly detailed airbrush painting, using a parametric equation to create captivating art, x(t) = A * cos(a * t) * cos(t) + A * sin(b * t) * cos(t) and y(t) = A * cos(a * t) * sin(t) + A * sin(b * t) * sin(t), where 'A', 'a', and 'b' are constants, and 't' ranges from 0 to 2π. By experimenting with different values for 'A', 'a', and 'b', you can generate a variety of intriguing and visually appealing designs, combine this with other artistic elements and styles to create a captivating abstract design --ar 3:2

https://discord.com/channels/1138810813491183726/1177609103791628329

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https:discord.comchannels10022921119426355621100170312106127410

https:discord.comchannels10022921119426355621100170312106127410

A highly detailed airbrush painting, using a parametric equation to create captivating art, x(t) = A * cos(a * t) * cos(t) + B* sin(b * t) * cos(t) and y(t) = A * cos(a * t) * sin(t) + B* sin(b * t) * sin(t), where 'A', 'B', 'a', and 'b' are constants, and 't' ranges from 0 to 2π. By experimenting with different values for 'A', 'B', 'a', and 'b', you can generate a variety of intriguing and visually appealing designs, combine this with other artistic elements and styles to create a captivating abstract design.

https://discord.com/channels/1002292111942635562/1100170312106127410/1196278267074859049

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会议,无聊,发呆,PPT,手机,困,瞌睡,电脑,眼睛,演示,饥饿

geometry,pen,japan

a graphical depiction of the relationship between the three trigonometric functions: sine, cosine, and tangent, with the unit circle in the background, abstract, highly detailed

https://discord.com/channels/662267976984297473/941582479117127680/1196267605007278191

https:discord.comchannels100229211194263556211037085041429258241183964186586398833,Generate line drawings

https://discord.com/channels/1002292111942635562/1108646783090958336/1194964314415702108

You can ask Chat GPT 😛

discord 里面可以直接邀请

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A highly detailed airbrush painting, using a parametric equation to createcaptivating art, x(t) = A * cos(a * t) * cost) + A *sin(b* t) * cost) and y(t) = A * cos(a *t) * sin(t) +A* sin(b * t) * sin(t), where A, a, and b are constants, and t ranges from 0 to 2n. By experimenting with different values for A, a, and b, you can generate a variety of intriguing and visually appealing designs, combine this with other artistic elements and styles to create a captivating abstract design --ar 3:2

you can ask chatGPT

On the phone screen, there is a post that has been replied to by many people.